Archive for May, 2012

Use math equation solver to solve complex equations

Posted on May 25, 2012. Filed under: Uncategorized | Tags: , , |

In the previous post we have discussed about How to work out linear equation calculator and In today’s session we are going to discuss about complex equations which falls under central board of secondary education,  When we study math equation solver, we say that the math equation solver help us to solve the mathematics equation and get the solution for the given equations. In case we have linear equations of one variable, then we can get the solution of the equation even by hit and trial methods. In this method, we say that we give different values to x and check that if any of the value satisfies the equation, then we say that particular value is the solution of the given linear equation in one variable. We can also solve the pair of linear equations with two variables either by plotting the graph or even by solving the pair of equations algebraically. (Know more about complex equations in broad manner, here,)

If we use the graphical method to solve the pair of linear equations with two variables, then we say that the two lines representing two equations can be plotted and thus we get the point of intersections of the two lines, which are plotted on the same graph. The meeting point of the two equations is called the solution of the pair of the linear equation. In case the two lines do not meet at all, then we say that the pair of equations does not have any solution. Thus we say that the two equations are parallel. On another hand if we have the graph of the two equations such that the two lines coincide each other then we say that the equations have more than one solution. In fact we observe that all the points of these two equations coincide and thus we find that the graph of the two equations overlap each other. SUCH EQUATIONS HAVE INFINITE SOLUTIONS>

This is all about the complex equations and if anyone want to know about Confidence Interval then they can refer Internet and text books for understanding it more precisely and Read more maths topics  such as  math tutor in the upcoming sessions here.

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How to work out linear equation calculator

Posted on May 25, 2012. Filed under: Uncategorized | Tags: , , |

In the previous post we have discussed about rational and irrational numbers and little bit about Two Step Linear Equation , In today’s session we are going to discuss about linear equation calculator which comes under syllabus of cbse class 9, In algebra, we deal with fixed as well as variable quantities. These quantities are termed as constants & variables respectively. Linear equations are the algebraic equations involving variables with degree one.

Since, the variables may acquire any value; it depends on a particular equation as to what value of the variable will satisfy the equation. Such a value of the variable in an equation is the solution to the equation.

A linear equation may have a variable either on one side of the equation only or on both the sides of the equation. To solve a linear equation in one variable; we should, first of all, bring all the like terms together. This can be done by the method of transposing in which terms are taken from one side of the equation to the other & their signs are changed in such shifting. Then the liked terms brought together are added or subtracted according to the sign they carry. Also the constant terms are solved for their signs. Thereafter the coefficient of the variable, if any, is also transposed to the other side of the equation to find the value of the variable. (want to Learn more about linear equation , click here),

It is worth mentioning here that during transposition of terms & coefficients of variables in an equation, the signs change as follows:

A positive sign changes to negative & vice versa.

Multiplication changes to division & vice versa.

Let us use the linear equation calculator to solve an equation & understand the concept.

5x + 4 = 7x – 6

To solve this equation, we will first collect the like terms on either side & we get the equation as

5x – 7x = -6 -4  ( transposing 7x to left hand side , it becomes -7x & 4 on transposing to left hand side            becomes -4)

·         – 2x = -10

·         x = -10 / (-2) [-2 which is being multiplied with x changes to division on transposing]

·         x = 5

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